Final answer to the problem
$y=\frac{\left(x-3\right)\left(x^2+4\right)}{\sqrt{3x^2+4x+5}}$
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- Find the derivative
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- Derivative
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1
For two logarithms of the same base to be equal, their arguments must be equal. In other words, if $\log(a)=\log(b)$ then $a$ must equal $b$
$y=\frac{\left(x-3\right)\left(x^2+4\right)}{\sqrt{3x^2+4x+5}}$
Final answer to the problem
$y=\frac{\left(x-3\right)\left(x^2+4\right)}{\sqrt{3x^2+4x+5}}$
