The integral $-\int\left(\frac{x^3}{3}-x^2+3x\right)\frac{1}{x}dx$ results in: $\frac{-x^{3}}{9}+\frac{1}{2}x^2-3x$
Gather the results of all integrals
As the integral that we are solving is an indefinite integral, when we finish integrating we must add the constant of integration $C$
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