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Exercise

$-x^2+7x-10=0$

Step-by-step Solution

1

Factor the trinomial by $-1$ for an easier handling

$-\left(x^2-7x+10\right)=0$
2

Factor the trinomial $-\left(x^2-7x+10\right)$ finding two numbers that multiply to form $10$ and added form $-7$

$\begin{matrix}\left(-2\right)\left(-5\right)=10\\ \left(-2\right)+\left(-5\right)=-7\end{matrix}$
3

Rewrite the polynomial as the product of two binomials consisting of the sum of the variable and the found values

$-\left(x^2-7x+10\right)=0$
4

Factor the trinomial $\left(x^2-7x+10\right)$ finding two numbers that multiply to form $10$ and added form $-7$

$\begin{matrix}\left(-2\right)\left(-5\right)=10\\ \left(-2\right)+\left(-5\right)=-7\end{matrix}$
5

Rewrite the polynomial as the product of two binomials consisting of the sum of the variable and the found values

$-\left(x-2\right)\left(x-5\right)=0$
6

Multiply both sides of the equation by $-1$

$\left(x-2\right)\left(x-5\right)=0$
7

Break the equation in $2$ factors and set each factor equal to zero, to obtain simpler equations

$x-2=0,\:x-5=0$
8

Solve the equation ($1$)

$x-2=0$
9

We need to isolate the dependent variable $x$, we can do that by simultaneously subtracting $-2$ from both sides of the equation

$x-2+2=0+2$
10

Canceling terms on both sides

$x=2$
11

Solve the equation ($2$)

$x-5=0$
12

We need to isolate the dependent variable $x$, we can do that by simultaneously subtracting $-5$ from both sides of the equation

$x-5+5=0+5$
13

Canceling terms on both sides

$x=5$
14

Combining all solutions, the $2$ solutions of the equation are

$x=2,\:x=5$

Final answer to the exercise

$x=2,\:x=5$

Try other ways to solve this exercise

  • Choose an option
  • Solve for x
  • Find the derivative using the definition
  • Solve by quadratic formula (general formula)
  • Simplify
  • Find the integral
  • Find the derivative
  • Factor
  • Factor by completing the square
  • Find the roots
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Main Topic: Differential Equations

A differential equation is a mathematical equation that relates some function with its derivatives.

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