Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Condense the logarithm
- Expand the logarithm
- Simplify
- Find the integral
- Find the derivative
- Write as single logarithm
- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
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The difference of two logarithms of equal base $b$ is equal to the logarithm of the quotient: $\log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right)$
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$\log_{2}\left(116\right)-\log_{2}\left(29\right)$
Learn how to solve differential calculus problems step by step online. Condense the logarithmic expression log2(3828)-log2(33)-log2(29). The difference of two logarithms of equal base b is equal to the logarithm of the quotient: \log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right). The difference of two logarithms of equal base b is equal to the logarithm of the quotient: \log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right). Decompose 4 in it's prime factors. Use the following rule for logarithms: \log_b(b^k)=k.