Simplify the expression $f\left(x\right)=\left(2x+2\right)\left(x^6+3x^3-4x\right)$

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Final answer to the problem

$f\left(x\right)=\left(2x+2\right)x\left(x^{4}+x^{3}+x^2+4x+4\right)\left(x-1\right)$
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Step-by-step Solution

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We can factor the polynomial $\left(x^6+3x^3-4x\right)$ using the rational root theorem, which guarantees that for a polynomial of the form $a_nx^n+a_{n-1}x^{n-1}+\dots+a_0$ there is a rational root of the form $\pm\frac{p}{q}$, where $p$ belongs to the divisors of the constant term $a_0$, and $q$ belongs to the divisors of the leading coefficient $a_n$. List all divisors $p$ of the constant term $a_0$, which equals $0$

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Learn how to solve algebraic expressions problems step by step online. Simplify the expression f(x)=(2x+2)(x^6+3x^3-4x). We can factor the polynomial \left(x^6+3x^3-4x\right) using the rational root theorem, which guarantees that for a polynomial of the form a_nx^n+a_{n-1}x^{n-1}+\dots+a_0 there is a rational root of the form \pm\frac{p}{q}, where p belongs to the divisors of the constant term a_0, and q belongs to the divisors of the leading coefficient a_n. List all divisors p of the constant term a_0, which equals 0. Next, list all divisors of the leading coefficient a_n, which equals 1. The possible roots \pm\frac{p}{q} of the polynomial \left(x^6+3x^3-4x\right) will then be. We can factor the polynomial \left(x^6+3x^3-4x\right) using synthetic division (Ruffini's rule). We found that 1 is a root of the polynomial.

Final answer to the problem

$f\left(x\right)=\left(2x+2\right)x\left(x^{4}+x^{3}+x^2+4x+4\right)\left(x-1\right)$

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Function Plot

Plotting: $f\left(x\right)-\left(2x+2\right)\left(x^6+3x^3-4x\right)$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Algebraic expressions

An algebraic expression is a group of terms that are separated by $+$ or $-$ signs.

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