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Since the integral $\int_{-1}^{1}\frac{1}{x^2}dx$ has a discontinuity inside the interval, we have to split it in two integrals
Learn how to solve definite integrals problems step by step online.
$\int_{-1}^{0}\frac{1}{x^2}dx+\int_{0}^{1}\frac{1}{x^2}dx$
Learn how to solve definite integrals problems step by step online. Integrate the function 1/(x^2) from -1 to 1. Since the integral \int_{-1}^{1}\frac{1}{x^2}dx has a discontinuity inside the interval, we have to split it in two integrals. The integral \int_{-1}^{0}\frac{1}{x^2}dx results in: \lim_{c\to0}\left(\frac{1}{-c}-1\right). The integral \int_{0}^{1}\frac{1}{x^2}dx results in: \lim_{c\to0}\left(-1+\frac{1}{c}\right). Gather the results of all integrals.
