Find the derivative of $\ln\left(\frac{\sqrt{-x+4}}{e^{\left(x^2\right)}\cos\left(3x^2+x\right)}\right)$

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Final answer to the problem

$\frac{-1}{2\left(-x+4\right)}-2x+\left(6x+1\right)\tan\left(3x^2+x\right)$
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Step-by-step Solution

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  • Find the derivative using the definition
  • Find the derivative using the product rule
  • Find the derivative using the quotient rule
  • Find the derivative using logarithmic differentiation
  • Find the derivative
  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
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1

Simplify the derivative by applying the properties of logarithms

$\frac{d}{dx}\left(\frac{1}{2}\ln\left(-x+4\right)-x^2-\ln\left(\cos\left(3x^2+x\right)\right)\right)$

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$\frac{d}{dx}\left(\frac{1}{2}\ln\left(-x+4\right)-x^2-\ln\left(\cos\left(3x^2+x\right)\right)\right)$

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Learn how to solve differential calculus problems step by step online. Find the derivative of ln(((-x+4)^(1/2))/(e^x^2cos(3x^2+x))). Simplify the derivative by applying the properties of logarithms. The derivative of a sum of two or more functions is the sum of the derivatives of each function. The derivative of a function multiplied by a constant is equal to the constant times the derivative of the function. The power rule for differentiation states that if n is a real number and f(x) = x^n, then f'(x) = nx^{n-1}.

Final answer to the problem

$\frac{-1}{2\left(-x+4\right)}-2x+\left(6x+1\right)\tan\left(3x^2+x\right)$

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Function Plot

Plotting: $\frac{-1}{2\left(-x+4\right)}-2x+\left(6x+1\right)\tan\left(3x^2+x\right)$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.

Used Formulas

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