Find the limit of $\frac{\sqrt[4]{3x^2+2x-1}}{\sqrt[3]{8x^3+1+2x}}$ as $x$ approaches $\infty $

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As it's an indeterminate limit of type $\frac{\infty}{\infty}$, divide both numerator and denominator by the term of the denominator that tends more quickly to infinity (the term that, evaluated at a large value, approaches infinity faster). In this case, that term is

$\lim_{x\to\infty }\left(\frac{\frac{\sqrt[4]{3x^2+2x-1}}{x}}{\frac{\sqrt[3]{8x^3+1+2x}}{x}}\right)$

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$\lim_{x\to\infty }\left(\frac{\frac{\sqrt[4]{3x^2+2x-1}}{x}}{\frac{\sqrt[3]{8x^3+1+2x}}{x}}\right)$

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Learn how to solve problems step by step online. Find the limit of ((3x^2+2x+-1)^(1/4))/((8x^3+12x)^(1/3)) as x approaches infinity. As it's an indeterminate limit of type \frac{\infty}{\infty}, divide both numerator and denominator by the term of the denominator that tends more quickly to infinity (the term that, evaluated at a large value, approaches infinity faster). In this case, that term is . Rewrite the fraction, in such a way that both numerator and denominator are inside the exponent or radical. Separate the terms of both fractions. Simplify the fraction \frac{8x^3}{x^{3}} by x^3.

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Plotting: $\frac{\sqrt[4]{3x^2+2x-1}}{\sqrt[3]{8x^3+1+2x}}$

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