Final answer to the problem
$\left(4a+9\right)\left(16a^{2}-36a+81\right)$
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Step-by-step Solution
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- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Prove from LHS (left-hand side)
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1
Factor the sum or difference of cubes using the formula: $a^3\pm b^3 = (a\pm b)(a^2\mp ab+b^2)$
Learn how to solve common monomial factor problems step by step online.
$\left(\sqrt[3]{64a^3}+\sqrt[3]{729}\right)\left(\sqrt[3]{\left(64a^3\right)^{2}}-\sqrt[3]{729}\sqrt[3]{64a^3}+\sqrt[3]{\left(729\right)^{2}}\right)$
Learn how to solve common monomial factor problems step by step online. Factor the expression 64a^3-729. Factor the sum or difference of cubes using the formula: a^3\pm b^3 = (a\pm b)(a^2\mp ab+b^2). Calculate the power \sqrt[3]{729}. Calculate the power \sqrt[3]{729}. Multiply -1 times 9.
Final answer to the problem
$\left(4a+9\right)\left(16a^{2}-36a+81\right)$
