Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Solve for x
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
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To find the roots of a polynomial of the form $ax^2+bx+c$ we use the quadratic formula, where in this case $a=4$, $b=-16$ and $c=13$. Then substitute the values of the coefficients of the equation in the quadratic formula: $\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
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$x=\frac{16\pm \sqrt{{\left(-16\right)}^2-4\cdot 4\cdot 13}}{2\cdot 4}$
Learn how to solve quadratic formula problems step by step online. Solve the quadratic equation 4x^2-16x+13=0. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=4, b=-16 and c=13. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Combining all solutions, the 2 solutions of the equation are.
