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Algebra Baldor
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Determine whether the expression $\sqrt[5]{3}$ is rational

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Solution

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Final answer to the problem

true

Step-by-step Solution

How should I solve this problem?

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  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
  • Integrate by parts
  • Integrate using tabular integration
  • Integrate by trigonometric substitution
  • Weierstrass Substitution
  • Prove from LHS (left-hand side)
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Apply the formula: $rational\left(a\right)$=true, where $a=\sqrt[5]{3}$

true

Final answer to the problem

true

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Function Plot

Plotting: $true$

Similar Problems Solved

$rational\left(\frac{1+irational\left(\sqrt{3}\right)}{18}\right)$

$rational2.1331333133331$

$rational7.466446644$

$rational1.4300$

$irrational2.1331333133331$

$irrational1.41352897$

$irrational\:\sqrt[3]{6125}$

Main Topic: Rationals and Irrationals

A rational term is an algebraic term that doesn't have literal part inside a radical. An irrational term does have literal part inside a radical.

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