Final answer to the problem
$22x^{8}+88x^{7}h+132x^{6}h^2+88x^{5}h^3+22h^4x^4$
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Step-by-step Solution
How should I solve this problem?
- Choose an option
- Product of Binomials with Common Term
- FOIL Method
- Find the integral
- Find the derivative
- Factor
- Integrate by partial fractions
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
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1
Expand the binomial $\left(x+h\right)^4$
$22\left(x^4+4x^3h+6x^2h^2+4xh^3+h^4\right)x^4$
Learn how to solve special products problems step by step online. Expand the expression 22(x+h)^4x^4. Expand the binomial \left(x+h\right)^4. Multiply the single term 22x^4 by each term of the polynomial \left(x^4+4x^3h+6x^2h^2+4xh^3+h^4\right). When multiplying exponents with same base we can add the exponents. When multiplying exponents with same base you can add the exponents: 88xh^3x^4.
Final answer to the problem
$22x^{8}+88x^{7}h+132x^{6}h^2+88x^{5}h^3+22h^4x^4$
