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- Integrate by partial fractions
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Rewrite the expression $\frac{x}{16x^4-1}$ inside the integral in factored form
Learn how to solve integrals by partial fraction expansion problems step by step online.
$\int\frac{x}{\left(4x^{2}+1\right)\left(4x^{2}-1\right)}dx$
Learn how to solve integrals by partial fraction expansion problems step by step online. Find the integral int(x/(16x^4-1))dx. Rewrite the expression \frac{x}{16x^4-1} inside the integral in factored form. Rewrite the fraction \frac{x}{\left(4x^{2}+1\right)\left(4x^{2}-1\right)} in 2 simpler fractions using partial fraction decomposition. Simplify the expression. The integral -\frac{1}{2}\int\frac{x}{4x^{2}+1}dx results in: -\frac{1}{16}\ln\left|4x^{2}+1\right|.