Expand the logarithmic expression $\log \left(86^{\left(86^x\right)}\right)$

Step-by-step Solution

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Final answer to the problem

$\log \left(2\right)86^x+\log \left(43\right)86^x$
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Step-by-step Solution

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  • Choose an option
  • Solve for x
  • Condense the logarithm
  • Expand the logarithm
  • Simplify
  • Find the integral
  • Find the derivative
  • Write as single logarithm
  • Integrate by partial fractions
  • Product of Binomials with Common Term
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Using the power rule of logarithms: $\log_a(x^n)=n\cdot\log_a(x)$

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$\log \left(86\right)86^x$

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Learn how to solve differential calculus problems step by step online. Expand the logarithmic expression log(86^86^x). Using the power rule of logarithms: \log_a(x^n)=n\cdot\log_a(x). Decompose 86 in it's prime factors. Use the product rule for logarithms: \log_b\left(MN\right)=\log_b\left(M\right)+\log_b\left(N\right), where M=2 and N=43. Multiply the single term 86^x by each term of the polynomial \left(\log \left(2\right)+\log \left(43\right)\right).

Final answer to the problem

$\log \left(2\right)86^x+\log \left(43\right)86^x$

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Plotting: $\log \left(2\right)86^x+\log \left(43\right)86^x$

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6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.

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