Final answer to the problem
$\sum_{n=0}^{\infty } \frac{{\left(-3\right)}^nx^{\left(4n+1\right)}}{\left(4n+1\right)\left(n!\right)}+C_0$
Got another answer? Verify it here!
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Integrate by partial fractions
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Integrate using trigonometric identities
- Integrate using basic integrals
- Product of Binomials with Common Term
- Load more...
Can't find a method? Tell us so we can add it.
1
Rewrite the function $e^{-3x^4}$ as it's representation in Maclaurin series expansion
Learn how to solve ascending and descending order problems step by step online.
$\int\sum_{n=0}^{\infty } \frac{\left(-3x^4\right)^n}{n!}dx$
Learn how to solve ascending and descending order problems step by step online. Find the integral int(e^(-3x^4))dx. Rewrite the function e^{-3x^4} as it's representation in Maclaurin series expansion. The power of a product is equal to the product of it's factors raised to the same power. Simplify \left(x^4\right)^n using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 4 and n equals n. We can rewrite the power series as the following.
Final answer to the problem
$\sum_{n=0}^{\infty } \frac{{\left(-3\right)}^nx^{\left(4n+1\right)}}{\left(4n+1\right)\left(n!\right)}+C_0$
