Final answer to the problem
$x\geq \frac{3x+y+10}{2}$
Got another answer? Verify it here!
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Prove from LHS (left-hand side)
- Load more...
Can't find a method? Tell us so we can add it.
1
Multiply the single term $2$ by each term of the polynomial $\left(x-5\right)$
$2x-10\geq 3x+y$
Learn how to solve two-variable linear inequalities problems step by step online.
$2x-10\geq 3x+y$
Learn how to solve two-variable linear inequalities problems step by step online. Solve the inequality 2(x-5)>=3x+y. Multiply the single term 2 by each term of the polynomial \left(x-5\right). Moving the term -10 to the other side of the inequation with opposite sign. Divide both sides of the inequation by 2.
Final answer to the problem
$x\geq \frac{3x+y+10}{2}$
