Final answer to the problem
$\frac{7m^{4}+79m^{3}-21n^{4}+28m^{3}n-42m^2n^{5}}{-7}$
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Step-by-step Solution
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- Write in simplest form
- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
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1
Factor the polynomial $7m^5+79m^4-21mn^4+28m^4n-42m^3n^5$ by it's greatest common factor (GCF): $m$
$\frac{m\left(7m^{4}+79m^{3}-21n^{4}+28m^{3}n-42m^2n^{5}\right)}{-7m}$
2
Simplify the fraction $\frac{m\left(7m^{4}+79m^{3}-21n^{4}+28m^{3}n-42m^2n^{5}\right)}{-7m}$ by $m$
$\frac{7m^{4}+79m^{3}-21n^{4}+28m^{3}n-42m^2n^{5}}{-7}$
Final answer to the problem
$\frac{7m^{4}+79m^{3}-21n^{4}+28m^{3}n-42m^2n^{5}}{-7}$