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- Derivative
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Multiply the single term $12$ by each term of the polynomial $\left(x-2\right)$
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$3\left(x-2\right)^2+2\left(y+1\right)^2+12x-16-4\left(y+1\right)=0$
Learn how to solve problems step by step online. Solve the equation 3(x-2)^2+2(y+1)^212(x-2)-4(y+1)+8=0. Multiply the single term 12 by each term of the polynomial \left(x-2\right). Multiply the single term -4 by each term of the polynomial \left(y+1\right). Expand \left(x-2\right)^2. Multiply the single term 3 by each term of the polynomial \left(x^2-4x+4\right).