Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Condense the logarithm
- Expand the logarithm
- Simplify
- Find the integral
- Find the derivative
- Write as single logarithm
- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Load more...
Using the power rule of logarithms: $\log_a(x^n)=n\cdot\log_a(x)$
Learn how to solve condensing logarithms problems step by step online.
$\log_{a}\left(x^2-1\right)-\log_{a}\left(x+1\right)+\frac{1}{2}\log_{a}\left(x-1\right)$
Learn how to solve condensing logarithms problems step by step online. Condense the logarithmic expression loga(x^2+-1)-loga(x+1)loga((x+-1)^(1/2)). Using the power rule of logarithms: \log_a(x^n)=n\cdot\log_a(x). The difference of two logarithms of equal base b is equal to the logarithm of the quotient: \log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right). The difference of the squares of two terms, divided by the sum of the same terms, is equal to the difference of the terms. In other words: \displaystyle\frac{a^2-b^2}{a+b}=a-b.. Combining like terms \frac{1}{2}\log_{a}\left(x-1\right) and \log_{a}\left(x-1\right).
