$y^3sen\left(2x\right)dx\:-\:3y^2cos^2dy\:=\:0$
$\lim_{x\to3}\left(\frac{7x^2-10x-3}{x-4}\right)$
$\frac{1}{3x-3}+\frac{1}{4x+4}=\frac{1}{12x-2}$
$125 h ^ { 9 } + k ^ { 12 }$
$\frac{1}{2}\left(6x+8\right)=2x+4+x$
$-\ln\left(x+1\right)+0.5\ln\left(1+x^2\right)$
$\left(-8-4xy\right)\left(-8+4xy\right)$
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