Final answer to the problem
$f\left(x\right)=\frac{\left(3x^2+2x-6\right)\sqrt{x^2+x+1}}{x^2\left(x+3\right)-2x\left(x+3\right)}$
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Step-by-step Solution
How should I solve this problem?
- Choose an option
- Write in simplest form
- Solve by quadratic formula (general formula)
- Find the derivative using the definition
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
- Load more...
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1
Multiply the single term $x\left(x+3\right)$ by each term of the polynomial $\left(x-2\right)$
Learn how to solve algebraic expressions problems step by step online.
$\frac{\left(3x^2+2x-6\right)\sqrt{x^2+x+1}}{x\cdot x\left(x+3\right)-2x\left(x+3\right)}$
Learn how to solve algebraic expressions problems step by step online. Simplify the expression f(x)=((3x^2+2x+-6)(x^2+x+1)^(1/2))/(x(x-2)(x+3)). Multiply the single term x\left(x+3\right) by each term of the polynomial \left(x-2\right). When multiplying two powers that have the same base (x), you can add the exponents.
Final answer to the problem
$f\left(x\right)=\frac{\left(3x^2+2x-6\right)\sqrt{x^2+x+1}}{x^2\left(x+3\right)-2x\left(x+3\right)}$
