Find the integral $\int\frac{1}{\left(x^2+\sqrt{2}+1\right)\left(x^2-\sqrt{2}+1\right)}dx$

Step-by-step Solution

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Final answer to the problem

$\frac{-169\arctan\left(\frac{x}{\sqrt{1+\sqrt{2}}}\right)}{478\sqrt{1+\sqrt{2}}}+\frac{0.3535534\arctan\left(\frac{x}{\sqrt{1-\sqrt{2}}}\right)}{\sqrt{1-\sqrt{2}}}+C_0$
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Step-by-step Solution

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  • Integrate by partial fractions
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Rewrite the fraction $\frac{1}{\left(x^2+\sqrt{2}+1\right)\left(x^2-\sqrt{2}+1\right)}$ in $2$ simpler fractions using partial fraction decomposition

$\frac{-169}{478\left(x^2+\sqrt{2}+1\right)}+\frac{0.3535534}{x^2-\sqrt{2}+1}$

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$\frac{-169}{478\left(x^2+\sqrt{2}+1\right)}+\frac{0.3535534}{x^2-\sqrt{2}+1}$

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Learn how to solve problems step by step online. Find the integral int(1/((x^2+2^(1/2)+1)(x^2-2^(1/2)+1)))dx. Rewrite the fraction \frac{1}{\left(x^2+\sqrt{2}+1\right)\left(x^2-\sqrt{2}+1\right)} in 2 simpler fractions using partial fraction decomposition. Expand the integral \int\left(\frac{-169}{478\left(x^2+\sqrt{2}+1\right)}+\frac{0.3535534}{x^2-\sqrt{2}+1}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\frac{-169}{478\left(x^2+\sqrt{2}+1\right)}dx results in: \frac{-169\arctan\left(\frac{x}{\sqrt{1+\sqrt{2}}}\right)}{478\sqrt{1+\sqrt{2}}}. The integral \int\frac{0.3535534}{x^2-\sqrt{2}+1}dx results in: \frac{0.3535534\arctan\left(\frac{x}{\sqrt{1-\sqrt{2}}}\right)}{\sqrt{1-\sqrt{2}}}.

Final answer to the problem

$\frac{-169\arctan\left(\frac{x}{\sqrt{1+\sqrt{2}}}\right)}{478\sqrt{1+\sqrt{2}}}+\frac{0.3535534\arctan\left(\frac{x}{\sqrt{1-\sqrt{2}}}\right)}{\sqrt{1-\sqrt{2}}}+C_0$

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Function Plot

Plotting: $\frac{-169\arctan\left(\frac{x}{\sqrt{1+\sqrt{2}}}\right)}{478\sqrt{1+\sqrt{2}}}+\frac{0.3535534\arctan\left(\frac{x}{\sqrt{1-\sqrt{2}}}\right)}{\sqrt{1-\sqrt{2}}}+C_0$

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0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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