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- Solve using L'Hôpital's rule
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- Integrate by partial fractions
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As it's an indeterminate limit of type $\frac{\infty}{\infty}$, divide both numerator and denominator by the term of the denominator that tends more quickly to infinity (the term that, evaluated at a large value, approaches infinity faster). In this case, that term is
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$\lim_{x\to\infty }\left(\frac{\frac{7-3x^2-5x^5}{x^4}}{\frac{2x^4-3x^3+2x-5}{x^4}}\right)$
Learn how to solve problems step by step online. Find the limit of (7-3x^2-5x^5)/(2x^4-3x^32x+-5) as x approaches infinity. As it's an indeterminate limit of type \frac{\infty}{\infty}, divide both numerator and denominator by the term of the denominator that tends more quickly to infinity (the term that, evaluated at a large value, approaches infinity faster). In this case, that term is . Separate the terms of both fractions. Simplify the fraction \frac{2x^4}{x^4} by x^4. Simplify the fraction by x.