Integrate the function $\frac{x+1}{x^a\sqrt{4+x^4}}$ from $1$ to $\infty $

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  • Integrate by partial fractions
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Expand the fraction $\frac{x+1}{x^a\sqrt{4+x^4}}$ into $2$ simpler fractions with common denominator $x^a\sqrt{4+x^4}$

$\int\left(\frac{x}{x^a\sqrt{4+x^4}}+\frac{1}{x^a\sqrt{4+x^4}}\right)dx$

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$\int\left(\frac{x}{x^a\sqrt{4+x^4}}+\frac{1}{x^a\sqrt{4+x^4}}\right)dx$

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Learn how to solve problems step by step online. Integrate the function (x+1)/(x^a(4+x^4)^(1/2)) from 1 to infinity. Expand the fraction \frac{x+1}{x^a\sqrt{4+x^4}} into 2 simpler fractions with common denominator x^a\sqrt{4+x^4}. Expand the integral \int\left(\frac{x}{x^a\sqrt{4+x^4}}+\frac{1}{x^a\sqrt{4+x^4}}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\frac{x}{x^a\sqrt{4+x^4}}dx results in: \frac{1}{2}\int\left(v^2-4\right)^{\left(-\frac{1}{2}-\frac{1}{4}a\right)}dv. The integral \int\frac{1}{x^a\sqrt{4+x^4}}dx results in: \frac{1}{2}\int\frac{1}{\left(u^2-4\right)^{\left(\frac{1}{4}a+\frac{3}{4}\right)}}du.

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