$25-4-9x+2$
$10x^2+x-21=0$
$\frac{y^{12}}{y^{-1}}$
$\frac{2x}{3}-\frac{5}{2}=\frac{x}{4}$
$\left(x+5\right)\cdot\left(2x-3\right)\cdot\left(6x-2\right)$
$y'=-2xy+7x$
$24+3f-12$
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