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- Integrate by partial fractions
- Integrate by substitution
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- Integrate using tabular integration
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- Weierstrass Substitution
- Exact Differential Equation
- Linear Differential Equation
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The integral of a function times a constant ($-1$) is equal to the constant times the integral of the function
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$-\int\frac{1}{1+y}dy=\int\frac{-1}{1-x}dx$
Learn how to solve problems step by step online. Solve the differential equation int(-1/(1+y))dy=int(-1/(1-x))dx. The integral of a function times a constant (-1) is equal to the constant times the integral of the function. Multiply both sides of the equation by -1. Solve the integral \int\frac{1}{1+y}dy and replace the result in the differential equation. Solve the integral -\int\frac{-1}{1-x}dx and replace the result in the differential equation.