$\frac{10x^2+7x-12}{2x+3}$
$\left(2x-7\right)\left(5x+3\right)$
$\sqrt{9-9x^2}$
$\frac{4}{x^2+x-380}$
$\left(-2\right)\left(3\right)-\left(3\right)\left(-1\right)\left(2\right)+\left(4\right)\left(3\right)$
$\frac{2}{3}\sqrt[3]{4m^2}.\frac{3}{4}\sqrt[5]{16m^4n}$
$\frac{da}{dt}=-10a+80t$
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