Solve the product $\left(9x^2y^3+xy^2z^4\right)\left(9x^2y^3-xy^2z^4\right)$

Step-by-step Solution

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Final answer to the problem

$81x^{4}y^{6}-x^2y^{4}z^{8}$
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Step-by-step Solution

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  • Product of Binomials with Common Term
  • FOIL Method
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The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: $(a+b)(a-b)=a^2-b^2$.

$\left(9x^2y^3\right)^2-\left(xy^2z^4\right)^2$

Learn how to solve quotient of powers problems step by step online.

$\left(9x^2y^3\right)^2-\left(xy^2z^4\right)^2$

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Learn how to solve quotient of powers problems step by step online. Solve the product (9x^2y^3+xy^2z^4)(9x^2y^3-xy^2z^4). The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2.. The power of a product is equal to the product of it's factors raised to the same power. The power of a product is equal to the product of it's factors raised to the same power. The power of a product is equal to the product of it's factors raised to the same power.

Final answer to the problem

$81x^{4}y^{6}-x^2y^{4}z^{8}$

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Function Plot

Plotting: $81x^{4}y^{6}-x^2y^{4}z^{8}$

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7
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9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Quotient of Powers

The quotient of powers of same base is equivalent to the same base to the power of the difference of exponents: $\frac{a^m}{a^n}=a^{m-n}$.

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