Solve the logarithmic equation $0.0405=\frac{1}{30}\ln\left(\frac{1050-30x}{-840}\right)$

Step-by-step Solution

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Final answer to the problem

$x=\frac{-3881.047014}{-30}$
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Step-by-step Solution

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Multiplying the fraction by $\ln\left(\frac{1050-30x}{-840}\right)$

$0.0405=\frac{\ln\left(\frac{1050-30x}{-840}\right)}{30}$

Learn how to solve logarithmic equations problems step by step online.

$0.0405=\frac{\ln\left(\frac{1050-30x}{-840}\right)}{30}$

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Unlock the first 3 steps of this solution

Learn how to solve logarithmic equations problems step by step online. Solve the logarithmic equation 0.0405=1/30ln((1050-30.0x)/-840.0). Multiplying the fraction by \ln\left(\frac{1050-30x}{-840}\right). Multiply both sides of the equation by 30. The logarithm of a quotient is equal to the logarithm of the numerator minus the logarithm of the denominator. We need to isolate the dependent variable x, we can do that by simultaneously subtracting -\ln\left(-840\right) from both sides of the equation.

Final answer to the problem

$x=\frac{-3881.047014}{-30}$

Exact Numeric Answer

$x=129.3682$

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Function Plot

Plotting: $0.0405+\frac{1}{30}\ln\left(\frac{1050-30x}{-840}\right)$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Logarithmic Equations

Are those equations in which the unknown variable appears within a logarithm.

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