Final answer to the problem
$\cot\left(x\right)+\frac{-e^x}{\tan\left(x\right)}$
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Step-by-step Solution
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- Choose an option
- Write in simplest form
- Solve by quadratic formula (general formula)
- Find the derivative using the definition
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
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1
Expand the fraction $\frac{1-e^x}{\tan\left(x\right)}$ into $2$ simpler fractions with common denominator $\tan\left(x\right)$
$\frac{1}{\tan\left(x\right)}+\frac{-e^x}{\tan\left(x\right)}$
2
Applying the trigonometric identity: $\cot\left(\theta\right)=\frac{1}{\tan\left(\theta\right)}$
$\cot\left(x\right)+\frac{-e^x}{\tan\left(x\right)}$
Final answer to the problem
$\cot\left(x\right)+\frac{-e^x}{\tan\left(x\right)}$
