Final answer to the problem
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- Write in simplest form
- Solve by quadratic formula (general formula)
- Find the derivative using the definition
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
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We can simplify the quotient of fractions $\frac{\frac{x^2+7x+10}{x^2-2x-8}}{\frac{x^2+6x+5}{x^2-3x-4}}$ by inverting the second fraction and multiply both fractions
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$\frac{\left(x^2+7x+10\right)\left(x^2-3x-4\right)}{\left(x^2-2x-8\right)\left(x^2+6x+5\right)}$
Learn how to solve factorization problems step by step online. Simplify the expression ((x^2+7x+10)/(x^2-2x+-8))/((x^2+6x+5)/(x^2-3x+-4)). We can simplify the quotient of fractions \frac{\frac{x^2+7x+10}{x^2-2x-8}}{\frac{x^2+6x+5}{x^2-3x-4}} by inverting the second fraction and multiply both fractions. Factor the trinomial \left(x^2+7x+10\right) finding two numbers that multiply to form 10 and added form 7. Rewrite the polynomial as the product of two binomials consisting of the sum of the variable and the found values. Factor the trinomial \left(x^2-3x-4\right) finding two numbers that multiply to form -4 and added form -3.
