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Exercise

$\frac{d}{dx}\left(\frac{\left(x^3-1\right)^{.5}\cdot\:\left(4\cdot\:x+1\right)^{.25}}{\left(x^5+3\right)^{\frac{1}{5}}}\right)$

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Final answer to the exercise

$\left(\frac{1.5x^{2}}{\left(x+1\right)\left(x^{2}-x+1\right)}+\frac{1}{4x+1}+\frac{-x^{4}}{x^5+3}\right)\frac{\left(x^3-1\right)^{0.5}\left(4x+1\right)^{0.25}}{\sqrt[5]{x^5+3}}$

Try other ways to solve this exercise

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  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
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