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- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
- Integrate by trigonometric substitution
- Weierstrass Substitution
- Prove from LHS (left-hand side)
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The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: $(a+b)(a-b)=a^2-b^2$.
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$4x\left(x+3\right)+x^2-4>\left(2x+3\right)^2+x-1$
Learn how to solve problems step by step online. Solve the inequality 4x(x+3)+(x+2)(x-2)>(2x+3)^2+x+-1. The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2.. Expand the expression \left(2x+3\right)^2 using the square of a binomial: (a+b)^2=a^2+2ab+b^2. Subtract the values 9 and -1. Combining like terms 12x and x.