Final answer to the problem
$x^x+2^x-0.5\ln\left(e^{2x}+2e^x+e^{\left(x^{0.5}\right)}\right)$
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Step-by-step Solution
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- Choose an option
- Write in simplest form
- Solve by quadratic formula (general formula)
- Find the derivative using the definition
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
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1
Using the power rule of logarithms: $\log_a(x^n)=n\cdot\log_a(x)$
$x^x+2^x-0.5\ln\left(e^{2x}+2e^x+e^{\left(x^{0.5}\right)}\right)$
Final answer to the problem
$x^x+2^x-0.5\ln\left(e^{2x}+2e^x+e^{\left(x^{0.5}\right)}\right)$
