Find the integral $\int e^{-\pi x^2}dx$

Step-by-step Solution

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acos
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sinh
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tanh
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asinh
acosh
atanh
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Final answer to the problem

$\sum_{n=0}^{\infty } \frac{{\left(-\pi \right)}^nx^{\left(2n+1\right)}}{\left(2n+1\right)\left(n!\right)}+C_0$
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Step-by-step Solution

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  • Integrate by partial fractions
  • Integrate by substitution
  • Integrate by parts
  • Integrate using tabular integration
  • Integrate by trigonometric substitution
  • Weierstrass Substitution
  • Integrate using trigonometric identities
  • Integrate using basic integrals
  • Product of Binomials with Common Term
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Rewrite the function $e^{-\pi x^2}$ as it's representation in Maclaurin series expansion

$\int\sum_{n=0}^{\infty } \frac{\left(-\pi x^2\right)^n}{n!}dx$

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$\int\sum_{n=0}^{\infty } \frac{\left(-\pi x^2\right)^n}{n!}dx$

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Unlock the first 3 steps of this solution

Learn how to solve problems step by step online. Find the integral int(e^(-pix^2))dx. Rewrite the function e^{-\pi x^2} as it's representation in Maclaurin series expansion. The power of a product is equal to the product of it's factors raised to the same power. Simplify \left(x^2\right)^n using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 2 and n equals n. We can rewrite the power series as the following.

Final answer to the problem

$\sum_{n=0}^{\infty } \frac{{\left(-\pi \right)}^nx^{\left(2n+1\right)}}{\left(2n+1\right)\left(n!\right)}+C_0$

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Function Plot

Plotting: $\sum_{n=0}^{\infty } \frac{{\left(-\pi \right)}^nx^{\left(2n+1\right)}}{\left(2n+1\right)\left(n!\right)}+C_0$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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