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Simplify the product $-(8x-4)$
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$\left(4x-1\right)^2+\left(-8x+4\right)\left(2x+8\right)\leq 5\left(x-4\right)-2\left(20x-5\right)-15$
Learn how to solve inequalities problems step by step online. Solve the inequality (4x-1)^2-(8x-4)(2x+8)<=5(x-4)-2(20x-5)+-15. Simplify the product -(8x-4). A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: (a-b)^2=a^2-2ab+b^2. The power of a product is equal to the product of it's factors raised to the same power. Multiply the single term 2x+8 by each term of the polynomial \left(-8x+4\right).
