Solve the equation $\frac{1}{5}\left(x+2y\right)+\frac{1}{10}y=\frac{7}{10}\left(x+1\right)-\frac{1}{2}-\frac{2}{5}$

Step-by-step Solution

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Final answer to the problem

$y=\frac{5x-2}{5}$
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Step-by-step Solution

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  • Solve for y
  • Find the derivative
  • Solve by implicit differentiation
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  • Derivative
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  • Solve by quadratic formula (general formula)
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Multiplying the fraction by $x+2y$

$\frac{x+2y}{5}+\frac{1}{10}y=\frac{7}{10}\left(x+1\right)-\frac{1}{2}-\frac{2}{5}$

Learn how to solve trigonometric identities problems step by step online.

$\frac{x+2y}{5}+\frac{1}{10}y=\frac{7}{10}\left(x+1\right)-\frac{1}{2}-\frac{2}{5}$

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Unlock the first 3 steps of this solution

Learn how to solve trigonometric identities problems step by step online. Solve the equation 1/5(x+2y)+1/10y=7/10(x+1)-1/2-2/5. Multiplying the fraction by x+2y. Solve the product \frac{7}{10}\left(x+1\right). Multiplying the fraction by y. Multiplying the fraction by x.

Final answer to the problem

$y=\frac{5x-2}{5}$

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Function Plot

Plotting: $\frac{1}{5}\left(x+2y\right)+\frac{1}{10}y+\frac{7}{10}\left(x+1\right)+\frac{1}{2}+\frac{2}{5}$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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