Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Solve using L'Hôpital's rule
- Solve without using l'Hôpital
- Solve using limit properties
- Solve using direct substitution
- Solve the limit using factorization
- Solve the limit using rationalization
- Integrate by partial fractions
- Product of Binomials with Common Term
- FOIL Method
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Evaluate the limit $\lim_{z\to0}\left(\frac{\sin\left(4z^2\right)+\cos\left(2z\right)-e^{-2z}}{\ln\left(z^2+1\right)+2z}\right)$ by replacing all occurrences of $z$ by $0$
Learn how to solve limits by direct substitution problems step by step online.
$\frac{\sin\left(4\cdot 0^2\right)+\cos\left(2\cdot 0\right)- e^{-2\cdot 0}}{\ln\left(0^2+1\right)+2\cdot 0}$
Learn how to solve limits by direct substitution problems step by step online. Find the limit of (sin(4z^2)+cos(2z)-e^(-2z))/(ln(z^2+1)+2z) as z approaches 0. Evaluate the limit \lim_{z\to0}\left(\frac{\sin\left(4z^2\right)+\cos\left(2z\right)-e^{-2z}}{\ln\left(z^2+1\right)+2z}\right) by replacing all occurrences of z by 0. Multiply 2 times 0. Multiply 2 times 0. Multiply -2 times 0.
