Final answer to the problem
$\frac{\left(x^2-5x+6\right)\left(2x^2-5x-3\right)}{\left(x^2-x+6\right)\left(x^2+6x+9\right)}$
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Step-by-step Solution
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1
We can simplify the quotient of fractions $\frac{\frac{x^2-5x+6}{x^2-x+6}}{\frac{x^2+6x+9}{2x^2-5x-3}}$ by inverting the second fraction and multiply both fractions
$\frac{\left(x^2-5x+6\right)\left(2x^2-5x-3\right)}{\left(x^2-x+6\right)\left(x^2+6x+9\right)}$
Final answer to the problem
$\frac{\left(x^2-5x+6\right)\left(2x^2-5x-3\right)}{\left(x^2-x+6\right)\left(x^2+6x+9\right)}$
