Final answer to the problem
$\frac{18u}{\sum_{n=0}^{\infty } \frac{u^{\left(n+2\right)}}{n!}+12ue^u}+\frac{-54u}{u^2e^u+36ue^u}+5\ln\left|s+6\right|+C_0$
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Step-by-step Solution
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- Integrate by partial fractions
- Integrate by substitution
- Integrate by parts
- Integrate using tabular integration
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- Weierstrass Substitution
- Integrate using trigonometric identities
- Integrate using basic integrals
- Product of Binomials with Common Term
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1
Solve the product $9\left(e^{-2s}-e^{-6s}\right)$
$\int\frac{9e^{-2s}-9e^{-6s}+5s}{s\left(s+6\right)}ds$
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$\int\frac{9e^{-2s}-9e^{-6s}+5s}{s\left(s+6\right)}ds$
Learn how to solve problems step by step online. Find the integral int((9(e^(-2s)-e^(-6s))+5s)/(s(s+6)))ds. Solve the product 9\left(e^{-2s}-e^{-6s}\right). Solve the product s\left(s+6\right). Expand the fraction \frac{9e^{-2s}-9e^{-6s}+5s}{s^2+6s} into 3 simpler fractions with common denominator s^2+6s. Simplify the expression.
Final answer to the problem
$\frac{18u}{\sum_{n=0}^{\infty } \frac{u^{\left(n+2\right)}}{n!}+12ue^u}+\frac{-54u}{u^2e^u+36ue^u}+5\ln\left|s+6\right|+C_0$
