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Solve the equation $\left(3x-7\right)^2-5\left(2x+1\right)\left(x-2\right)=-\left(x+2\right)^2+4x+9$

Step-by-step Solution

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Solution

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Final answer to the problem

$x=2$
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Step-by-step Solution

How should I solve this problem?

  • Choose an option
  • Solve for x
  • Find the derivative using the definition
  • Solve by quadratic formula (general formula)
  • Simplify
  • Find the integral
  • Find the derivative
  • Factor
  • Factor by completing the square
  • Find the roots
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Move everything to the left hand side of the equation

Learn how to solve definite integrals problems step by step online.

$\left(3x-7\right)^2-5\left(2x+1\right)\left(x-2\right)+\left(x+2\right)^2-4x-9=0$

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Unlock the first 3 steps of this solution

Learn how to solve definite integrals problems step by step online. Solve the equation (3x-7)^2-5(2x+1)(x-2)=-(x+2)^2+4x+9. Move everything to the left hand side of the equation. Expand \left(3x-7\right)^2. Subtract the values 49 and -9. Combining like terms -42x and -4x.

Final answer to the problem

$x=2$

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Function Plot

Plotting: $\left(3x-7\right)^2-5\left(2x+1\right)\left(x-2\right)+\left(x+2\right)^2-4x-9$

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5
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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

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Main Topic: Definite Integrals

Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b

Used Formulas

See formulas (1)

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