Final answer to the problem
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Solve for x
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
- Find the roots
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The difference of two logarithms of equal base $b$ is equal to the logarithm of the quotient: $\log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right)$
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$\log \left(\frac{3x}{2}\right)=-1$
Learn how to solve problems step by step online. Solve the logarithmic equation log(3*x)-log(2)=-1. The difference of two logarithms of equal base b is equal to the logarithm of the quotient: \log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right). Express the numbers in the equation as logarithms of base 10. For two logarithms of the same base to be equal, their arguments must be equal. In other words, if \log(a)=\log(b) then a must equal b. Applying the property of exponents, \displaystyle a^{-n}=\frac{1}{a^n}, where n is a number.
