Final answer to the problem
$x=\frac{-1998.5190674}{-30}$
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Step-by-step Solution
How should I solve this problem?
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- Solve for x
- Find the derivative using the definition
- Solve by quadratic formula (general formula)
- Simplify
- Find the integral
- Find the derivative
- Factor
- Factor by completing the square
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1
Multiplying the fraction by $\ln\left(\frac{1050-30x}{-840}\right)$
$0.0405=\frac{\ln\left(\frac{1050-30x}{-840}\right)}{3}$
Learn how to solve logarithmic equations problems step by step online.
$0.0405=\frac{\ln\left(\frac{1050-30x}{-840}\right)}{3}$
Learn how to solve logarithmic equations problems step by step online. Solve the logarithmic equation 0.0405=1/3ln((1050-30.0x)/-840.0). Multiplying the fraction by \ln\left(\frac{1050-30x}{-840}\right). Multiply both sides of the equation by 3. The logarithm of a quotient is equal to the logarithm of the numerator minus the logarithm of the denominator. We need to isolate the dependent variable x, we can do that by simultaneously subtracting -\ln\left(-840\right) from both sides of the equation.
Final answer to the problem
$x=\frac{-1998.5190674}{-30}$
Exact Numeric Answer
$x=66.6173$
