Solve the exponential equation $e^{\left(3x+7\right)}=128^{\left(ex+9\right)}$

Step-by-step Solution

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Final answer to the problem

$x=\frac{63\ln\left(2\right)-7}{3-1e\ln\left(128\right)}$
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Step-by-step Solution

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Decompose $128$ in it's prime factors

$e^{\left(3x+7\right)}=\left(2^{7}\right)^{\left(ex+9\right)}$

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$e^{\left(3x+7\right)}=\left(2^{7}\right)^{\left(ex+9\right)}$

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Learn how to solve problems step by step online. Solve the exponential equation e^(3x+7)=128^(ex+9). Decompose 128 in it's prime factors. Simplify \left(2^{7}\right)^{\left(ex+9\right)} using the power of a power property: \left(a^m\right)^n=a^{m\cdot n}. In the expression, m equals 7 and n equals ex+9. Solve the product 7\left(ex+9\right). We can take out the unknown from the exponent by applying natural logarithm to both sides of the equation.

Final answer to the problem

$x=\frac{63\ln\left(2\right)-7}{3-1e\ln\left(128\right)}$

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Function Plot

Plotting: $e^{\left(3x+7\right)}- 128^{\left(ex+9\right)}$

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5
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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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