$5x\:+3-3x-2x-3x-2x$
$2^2\:x\:2^3$
$2-2+1+7$
$5\sin^2\left(x\right)\:+\:3\tan^2\left(x\right)$
$\frac{x^3-1}{x^1-1}$
$\int\frac{-2x^2+8x+8}{\left(x^2+4\right)\left(x-2\right)^3}dx$
$y=\frac{2}{x}-\frac{1}{x^{2}}$
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