Final answer to the problem
$\ln\left(\left(\mathrm{cosh}\left(4x\right)+\mathrm{sinh}\left(4x\right)\right)\left(\mathrm{cosh}\left(3x\right)-\mathrm{sinh}\left(3x\right)\right)\right)$
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Solve for x
- Condense the logarithm
- Expand the logarithm
- Simplify
- Find the integral
- Find the derivative
- Write as single logarithm
- Integrate by partial fractions
- Product of Binomials with Common Term
- Load more...
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1
Math interpretation of the question
$\ln\left(\mathrm{cosh}\left(4x\right)+\mathrm{sinh}\left(4x\right)\right)+\ln\left(\mathrm{cosh}\left(3x\right)-\mathrm{sinh}\left(3x\right)\right)$
2
Applying the product rule for logarithms: $\log_b\left(MN\right)=\log_b\left(M\right)+\log_b\left(N\right)$
$\ln\left(\left(\mathrm{cosh}\left(4x\right)+\mathrm{sinh}\left(4x\right)\right)\left(\mathrm{cosh}\left(3x\right)-\mathrm{sinh}\left(3x\right)\right)\right)$
Final answer to the problem
$\ln\left(\left(\mathrm{cosh}\left(4x\right)+\mathrm{sinh}\left(4x\right)\right)\left(\mathrm{cosh}\left(3x\right)-\mathrm{sinh}\left(3x\right)\right)\right)$
