$y=\left(1+\cot\left(x\right)\right)^2$

$\frac{5m+25}{14}\cdot\frac{7m+7}{10m+50}$

$x\left(x-20\right)$

$-5\left(-4y+4z\right)+4\left(-5z-y\right)$

$\int\frac{\left(4x^2+7x-3\right)}{\left(x+1\right)^2\left(x-2\right)}dx$

$\frac{tan\left(x\right)+cot\left(x\right)}{csc\left(x\right)}$

$\sqrt[3]{5x+3y}=x^2$