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- Solve using L'Hôpital's rule
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- Integrate by partial fractions
- Product of Binomials with Common Term
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As it's an indeterminate limit of type $\frac{\infty}{\infty}$, divide both numerator and denominator by the term of the denominator that tends more quickly to infinity (the term that, evaluated at a large value, approaches infinity faster). In this case, that term is
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$\lim_{x\to\infty }\left(\frac{\frac{6x^4+3x^5-2x^2}{x^5}}{\frac{9x^2+4x^4+2x^5}{x^5}}\right)$
Learn how to solve problems step by step online. Find the limit of (6x^4+3x^5-2x^2)/(9x^2+4x^42x^5) as x approaches infinity. As it's an indeterminate limit of type \frac{\infty}{\infty}, divide both numerator and denominator by the term of the denominator that tends more quickly to infinity (the term that, evaluated at a large value, approaches infinity faster). In this case, that term is . Separate the terms of both fractions. Simplify the fraction . Simplify the fraction by x.
