Final answer to the problem
$\log_{2}\left(x\right)+\log_{2}\left(e\right)x$
Got another answer? Verify it here!
Step-by-step Solution
How should I solve this problem?
- Choose an option
- Solve for x
- Condense the logarithm
- Expand the logarithm
- Simplify
- Find the integral
- Find the derivative
- Write as single logarithm
- Integrate by partial fractions
- Product of Binomials with Common Term
- Load more...
Can't find a method? Tell us so we can add it.
1
Use the product rule for logarithms: $\log_b\left(MN\right)=\log_b\left(M\right)+\log_b\left(N\right)$, where $M=x$ and $N=e^x$
$\log_{2}\left(x\right)+\log_{2}\left(e^x\right)$
2
Using the power rule of logarithms: $\log_a(x^n)=n\cdot\log_a(x)$
$\log_{2}\left(x\right)+\log_{2}\left(e\right)x$
Final answer to the problem
$\log_{2}\left(x\right)+\log_{2}\left(e\right)x$
