Find the integral $\int\frac{x^2}{\sqrt{x^2+6}}dx$

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Final answer to the problem

$-3\ln\left|\sqrt{x^2+6}+x\right|+\frac{1}{2}x\sqrt{x^2+6}+C_1$
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Step-by-step Solution

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  • Integrate by partial fractions
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1

We can solve the integral $\int\frac{x^2}{\sqrt{x^2+6}}dx$ by applying integration method of trigonometric substitution using the substitution

$x=\sqrt{6}\tan\left(\theta \right)$

Differentiate both sides of the equation $x=\sqrt{6}\tan\left(\theta \right)$

$dx=\frac{d}{d\theta}\left(\sqrt{6}\tan\left(\theta \right)\right)$

Find the derivative

$\frac{d}{d\theta}\left(\sqrt{6}\tan\left(\theta \right)\right)$

The derivative of a function multiplied by a constant is equal to the constant times the derivative of the function

$\sqrt{6}\frac{d}{d\theta}\left(\tan\left(\theta \right)\right)$

The derivative of the tangent of a function is equal to secant squared of that function times the derivative of that function, in other words, if ${f(x) = tan(x)}$, then ${f'(x) = sec^2(x)\cdot D_x(x)}$

$\sqrt{6}\frac{d}{d\theta}\left(\theta \right)\sec\left(\theta \right)^2$

The derivative of the linear function is equal to $1$

$\sqrt{6}\sec\left(\theta \right)^2$
2

Now, in order to rewrite $d\theta$ in terms of $dx$, we need to find the derivative of $x$. We need to calculate $dx$, we can do that by deriving the equation above

$dx=\sqrt{6}\sec\left(\theta \right)^2d\theta$

The power of a product is equal to the product of it's factors raised to the same power

$\int\sqrt{6}\frac{6\tan\left(\theta \right)^2}{\sqrt{\left(\sqrt{6}\tan\left(\theta \right)\right)^2+6}}\sec\left(\theta \right)^2d\theta$

Multiplying the fraction by $\sqrt{6}\sec\left(\theta \right)^2$

$\int\frac{6\sqrt{6}\tan\left(\theta \right)^2\sec\left(\theta \right)^2}{\sqrt{\left(\sqrt{6}\tan\left(\theta \right)\right)^2+6}}d\theta$

The power of a product is equal to the product of it's factors raised to the same power

$\int\frac{6\sqrt{6}\tan\left(\theta \right)^2\sec\left(\theta \right)^2}{\sqrt{6\tan\left(\theta \right)^2+6}}d\theta$

Simplify $6\tan\left(\theta \right)^2+6$ into secant function

$\int\frac{6\sqrt{6}\tan\left(\theta \right)^2\sec\left(\theta \right)^2}{\sqrt{6\sec\left(\theta \right)^2}}d\theta$

The power of a product is equal to the product of it's factors raised to the same power

$\int\frac{6\sqrt{6}\tan\left(\theta \right)^2\sec\left(\theta \right)^2}{\sqrt{6}\sec\left(\theta \right)}d\theta$

Simplify the fraction $\frac{6\sqrt{6}\tan\left(\theta \right)^2\sec\left(\theta \right)^2}{\sqrt{6}\sec\left(\theta \right)}$ by $\sqrt{6}$

$\int\frac{6\tan\left(\theta \right)^2\sec\left(\theta \right)^2}{\sec\left(\theta \right)}d\theta$
3

Substituting in the original integral, we get

$\int\frac{6\tan\left(\theta \right)^2\sec\left(\theta \right)^2}{\sec\left(\theta \right)}d\theta$

Simplify the fraction $\frac{6\tan\left(\theta \right)^2\sec\left(\theta \right)^2}{\sec\left(\theta \right)}$ by $\sec\left(\theta \right)$

$\int6\tan\left(\theta \right)^2\sec\left(\theta \right)d\theta$
4

Simplifying

$\int6\tan\left(\theta \right)^2\sec\left(\theta \right)d\theta$
5

The integral of a function times a constant ($6$) is equal to the constant times the integral of the function

$6\int\tan\left(\theta \right)^2\sec\left(\theta \right)d\theta$

Applying the trigonometric identity: $\tan\left(\theta \right)^2 = \sec\left(\theta \right)^2-1$

$6\int\left(\sec\left(\theta \right)^2-1\right)\sec\left(\theta \right)d\theta$
6

We identify that the integral has the form $\int\tan^m(x)\sec^n(x)dx$. If $n$ is odd and $m$ is even, then we need to express everything in terms of secant, expand and integrate each function separately

$6\int\left(\sec\left(\theta \right)^2-1\right)\sec\left(\theta \right)d\theta$

Multiply the single term $\sec\left(\theta \right)$ by each term of the polynomial $\left(\sec\left(\theta \right)^2-1\right)$

$\int\left(\sec\left(\theta \right)^2\sec\left(\theta \right)-\sec\left(\theta \right)\right)$

When multiplying exponents with same base you can add the exponents: $\sec\left(\theta \right)^2\sec\left(\theta \right)$

$6\int\left(\sec\left(\theta \right)^{3}-\sec\left(\theta \right)\right)d\theta$
7

Multiply the single term $\sec\left(\theta \right)$ by each term of the polynomial $\left(\sec\left(\theta \right)^2-1\right)$

$6\int\left(\sec\left(\theta \right)^{3}-\sec\left(\theta \right)\right)d\theta$
8

Expand the integral $\int\left(\sec\left(\theta \right)^{3}-\sec\left(\theta \right)\right)d\theta$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately

$6\int\sec\left(\theta \right)^{3}d\theta-6\int\sec\left(\theta \right)d\theta$

Simplify the integral $\int\sec\left(\theta \right)^{3}d\theta$ applying the reduction formula, $\displaystyle\int\sec(x)^{n}dx=\frac{\sin(x)\sec(x)^{n-1}}{n-1}+\frac{n-2}{n-1}\int\sec(x)^{n-2}dx$

$6\left(\frac{\sin\left(\theta \right)\sec\left(\theta \right)^{2}}{2}+\frac{1}{2}\int\sec\left(\theta \right)d\theta\right)$

Solve the product $6\left(\frac{\sin\left(\theta \right)\sec\left(\theta \right)^{2}}{2}+\frac{1}{2}\int\sec\left(\theta \right)d\theta\right)$

$6\left(\frac{\sin\left(\theta \right)\sec\left(\theta \right)^{2}}{2}\right)+3\int\sec\left(\theta \right)d\theta$

Simplify the fraction $6\left(\frac{\sin\left(\theta \right)\sec\left(\theta \right)^{2}}{2}\right)$

$3\sin\left(\theta \right)\sec\left(\theta \right)^{2}+3\int\sec\left(\theta \right)d\theta$

Express the variable $\theta$ in terms of the original variable $x$

$\frac{1}{2}x\sqrt{x^2+6}+3\int\sec\left(\theta \right)d\theta$

The integral of the secant function is given by the following formula, $\displaystyle\int\sec(x)dx=\ln\left|\sec(x)+\tan(x)\right|$

$\frac{1}{2}x\sqrt{x^2+6}+3\ln\left|\sec\left(\theta \right)+\tan\left(\theta \right)\right|$

Express the variable $\theta$ in terms of the original variable $x$

$\frac{1}{2}x\sqrt{x^2+6}+3\ln\left|\frac{\sqrt{x^2+6}+x}{\sqrt{6}}\right|$
9

The integral $6\int\sec\left(\theta \right)^{3}d\theta$ results in: $\frac{1}{2}x\sqrt{x^2+6}+3\ln\left(\frac{\sqrt{x^2+6}+x}{\sqrt{6}}\right)$

$\frac{1}{2}x\sqrt{x^2+6}+3\ln\left(\frac{\sqrt{x^2+6}+x}{\sqrt{6}}\right)$
10

Gather the results of all integrals

$3\ln\left|\frac{\sqrt{x^2+6}+x}{\sqrt{6}}\right|+\frac{1}{2}x\sqrt{x^2+6}-6\int\sec\left(\theta \right)d\theta$

The integral of the secant function is given by the following formula, $\displaystyle\int\sec(x)dx=\ln\left|\sec(x)+\tan(x)\right|$

$-6\ln\left|\sec\left(\theta \right)+\tan\left(\theta \right)\right|$

Express the variable $\theta$ in terms of the original variable $x$

$-6\ln\left|\frac{\sqrt{x^2+6}+x}{\sqrt{6}}\right|$
11

The integral $-6\int\sec\left(\theta \right)d\theta$ results in: $-6\ln\left(\frac{\sqrt{x^2+6}+x}{\sqrt{6}}\right)$

$-6\ln\left(\frac{\sqrt{x^2+6}+x}{\sqrt{6}}\right)$
12

Gather the results of all integrals

$3\ln\left|\frac{\sqrt{x^2+6}+x}{\sqrt{6}}\right|+\frac{1}{2}x\sqrt{x^2+6}-6\ln\left|\frac{\sqrt{x^2+6}+x}{\sqrt{6}}\right|$
13

Combining like terms $3\ln\left(\frac{\sqrt{x^2+6}+x}{\sqrt{6}}\right)$ and $-6\ln\left(\frac{\sqrt{x^2+6}+x}{\sqrt{6}}\right)$

$-3\ln\left|\frac{\sqrt{x^2+6}+x}{\sqrt{6}}\right|+\frac{1}{2}x\sqrt{x^2+6}$
14

As the integral that we are solving is an indefinite integral, when we finish integrating we must add the constant of integration $C$

$-3\ln\left|\frac{\sqrt{x^2+6}+x}{\sqrt{6}}\right|+\frac{1}{2}x\sqrt{x^2+6}+C_0$
15

Simplify the expression by applying the property of the logarithm of a quotient

$-3\ln\left|\sqrt{x^2+6}+x\right|+\frac{1}{2}x\sqrt{x^2+6}+C_1$

Final answer to the problem

$-3\ln\left|\sqrt{x^2+6}+x\right|+\frac{1}{2}x\sqrt{x^2+6}+C_1$

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Function Plot

Plotting: $-3\ln\left(\sqrt{x^2+6}+x\right)+\frac{1}{2}x\sqrt{x^2+6}+C_1$

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x
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.
(◻)
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◻/◻
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2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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